It does not. If you enforce 0/0=1, then you end up in a situation where you can prove any two numbers are equal to each other and you end up with a useless system, so we do not allow for that.
e.g. 0=0*2 -> 0/0 = (0/0)*2 -> 1=1*2 -> 1=2
If you get into calculus though, you’ll have ways to deal with this to some extent using limits.
It does not. If you enforce 0/0=1, then you end up in a situation where you can prove any two numbers are equal to each other and you end up with a useless system, so we do not allow for that.
e.g. 0=0*2 -> 0/0 = (0/0)*2 -> 1=1*2 -> 1=2
If you get into calculus though, you’ll have ways to deal with this to some extent using limits.
Quick tip, Markdown treats * specially so you need to escape it like so: \*
Thanks. I already fixed it, but it seems Lemmy is just slow to propagate edits.
I see you replace two “0” with a “0/0”, but why that? Since you assume it equals 1, why do you replace it for 0?
I’m dividing both sides by 0.
Ah, yes. Normally not allowed because undefined, but here you define it as 1. Alright, thanks.